Question

x-y+2[x-{x-(x+y-2) -1} +1]

Answer 1

Hey!

Answer:

Let's simplify step-by-step.

x−y+2(x−(x−(x+y−2)−1)+1)

Distribute:

=x+−y+(2)(x)+(2)(−x)+(2)(x)+(2)(y)+(2)(−2)+(2)(1)+(2)(1)

=x+−y+2x+−2x+2x+2y+−4+2+2

Combine Like Terms:

=x+−y+2x+−2x+2x+2y+−4+2+2

=(x+2x+−2x+2x)+(−y+2y)+(−4+2+2)

=3x+y ANSWER

:)

Step-by-step explanation:

Answer 2

x - y + 2[x - {x - (x + y - 2) - 1} + 1]

Answer:

First, let's open/simplify the inner most bracket.

x - y + 2[x - {x - (x + y - 2) - 1} + 1]

x - y + 2[x - {x - x - y + 2 - 1} + 1]

Now the next set.

x - y + 2[x - {x - x - y + 2 - 1} + 1]

x - y + 2[x - x + x + y - 2 + 1 + 1]

Let us simplify the above equation.

x - y + 2[x + y - 1 + 1]

Now the final bracket.

x - y + 2[x + y - 1 + 1]

x - y + 2x + 2y - 2 + 2

Let us arrange them for easy simplification.

x + 2x - y + 2y - 2 + 2

Simplifying it,

3x + 1y

Hope it helps :)