Question

( x + y ) ^2 = ( x-y ) ^2 +4xy

Answer 1

Step-by-step explanation:

$x {}^{2} + 2xy + {y}^{2} = {x}^{2} - 2xy + 4xy + {y}^{2}$

${x}^{2} + 2xy + {y}^{2} = {x}^{2} + 2xy + {y}^{2}$