Math, asked by ars73, 1 year ago

(x+y)^2×(x-y)^2=??? please help

Answers

Answered by Anonymous
19

Answer:

= x^4 + y^4 - 2x²y²

Step-by-step explanation:

(x+y)^2 = x^2 + y^2 + 2xy

(x-y)^2 = x^2 + y^2 - 2xy


(x+y)^2 * (x-y)^2 = ( x^2 + y^2 + 2xy)*( x^2 + y^2 - 2xy)

= x^4 + x²y² - 2x³y + y^4 + x²y² - 2xy³ + 2x³y + 2xy³ - 4x²y²

= x^4 + y^4 - 2x²y²


ars73: thanks....
Answered by Anonymous
4
HIII MATE!!!

SOLUTION:-


BY STEP BY STEP EXPLAINATION


(x + y) { }^{2} (x - y) {}^{2}

Simplifying 1st term:-


(x + y) {}^{2}

x ^{2}  + 2xy + y {}^{2}

-------------------------------(1)

Simplifing 2nd term:-


(x - y) {}^{2}


x ^{2}  - 2xy + y {}^{2}
---------------------------------(2)



MULTIPLYING ------(1) and------(2),we get:-


(x ^{2}  + 2xy + y {}^{2} )(x {}^{2}  - 2xy + y {}^{2} )


x ^{2} (x {}^{2}  - 2xy + y {}^{2} ) + 2xy (x {}^{2}  - 2xy + y {}^{2} ) + y {}^{2}  (x {}^{2}  - 2xy + y {}^{2} )


x ^{4}   - 2x {}^{2} y {}^{2}  + y { }^{4}


THANKS
I THINK IT HELPS....
@garu1678


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