Question

x-y = 28 and x-3y=0 by substitution​

Answer 1

Answer:

$\large\boxed{\sf{x=42,\;y=14}}$

Step-by-step explanation:

Given a pair of linear equations such that,

x - y = 28 .......(1)

x - 3y = 0 ........(2)

Now, we have to find the values of x and y by substitution method.

For this, let's solve eqn (2).

From eqn (2), we get,

=> x = 3y

Now, substitute this value of x in eqn (1),

Therefore, we will get,

=> 3y - y = 28

=> 2y = 28

=> y = 28/2

=> y = 14

Now, putting this value , ww have,

=> x = 3 × 14

=> x = 42

Hence, the values of x = 42 and y =14.

Answer 2

$\huge\bold{SoluTion:}$

Given equations :

• x - y = 28........(1)

• x - 3y = 0.........(2)

From eq (2),

$\mapsto$ x = 3y

Put x = 3y in eq (1)

$\mapsto$ 3y - y = 28

$\mapsto$ 2y = 28

$\mapsto$ y = $\dfrac{28}{2}$

$\mapsto$ y = 14

Now, put y = 14 in (1),

$\mapsto$ x - 14 = 28

$\mapsto$ x = 28 + 14

$\mapsto$ x = 42

$\rule{200}2$

Therefore, value of x and y are 42 and 14 respectively.