(x+y)(2x+3y)subtract(x+y)(x+1)
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the answer is x^2+4xy-x-y
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= (x + y)(2x + 3y) - (x + y)(x +1)
= (2x^2 + 3xy + 2xy + 3y^2) - (x^2 + x + xy + y)
= 2x^2 + 5xy + 3y^2 - x^2 - x - xy - y
= x^2 + 3y^2 + 4xy - x - y ans..
= (2x^2 + 3xy + 2xy + 3y^2) - (x^2 + x + xy + y)
= 2x^2 + 5xy + 3y^2 - x^2 - x - xy - y
= x^2 + 3y^2 + 4xy - x - y ans..
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