Question

X+y=2z find x/x-z + z/y-z

Answer 1

$\textbf{Given:}$

$x+y=2z$

$\implies\;x+y=z+z$

$\implies\;x-z=z-y$

$\text{Now}$

$\frac{x}{x-z}+\frac{z}{y-z}$

$\implies\frac{x}{x-z}+\frac{z}{-(z-y)}$

$\implies\frac{x}{x-z}-\frac{z}{z-y}$

$\implies\frac{x}{x-z}-\frac{z}{x-z}$

$\implies\frac{x-z}{x-z}$

$\implies\;1$

$\therefore\boxed{\bf\frac{x}{x-z}+\frac{z}{y-z}=1}$

Answer 2

Answer:

1

Step-by-step explanation:

$x+y=2z\\\\x-z=z-y\\\\\\\frac{x-z}{z-y}=1\\\\\frac{x}{z-y}-\frac{z}{z-y}=1\\\\sub\;\;z-y=x-z\;\;in\;\;the\;\;first\;\;term\\\\\frac{x}{x-z}+\frac{z}{-(z-y)}=1\\\\\frac{x}{x-z}+\frac{z}{y-z}=1$

Hope it Helps