X-y=3;2x-y=11 using cross multiplication
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Answer:
x - y = 3
so, x - y - 3 = 0
let 1 = a1
let -1 = b1
let -3 = c1
2x - y = 11
so,
2x - y - 11 = 0
let 2 = a2
let -1 = b2
let -11 = c2
x/(b1 * c2) - (b2 * c1) = y/(c1 * a2) - (c2 * a1) = 1/(a1 *b2) - (a2 * b1)
so,
x/(-1)(-11) - (-1)(-3) = y/(-3)(2) - (-11)(1) = 1/(1)(-1) - (2)(-1)
x/ 11 - 3 = y/ -6 + 11 = 1/ -1 + 2
x/8 = y/5 = 1/1
so,
x = 8/1 = 8
y = 5/1 = 5
Therefore,
x = 8 and
y = 5
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