x+y=3 and xy=2 then find x^2+y^2
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Answered by
1
Hi here is your answer I wish that it must help u
X square plus y square = [x plus y ]^2 - 2xy
= (3^2)-(2*2)
= 9-4= 5
X square plus y square = [x plus y ]^2 - 2xy
= (3^2)-(2*2)
= 9-4= 5
Answered by
0
x+y=3
xy=2
x^2+y^2
(X+y)^2
X^2+y^2+2xy
(X+y)^2+2xy
(3)^2+2(2)
9+4
13
xy=2
x^2+y^2
(X+y)^2
X^2+y^2+2xy
(X+y)^2+2xy
(3)^2+2(2)
9+4
13
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