Question

(x-y)^3 - (x-y)^3 ???????????​

Answer 1

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Answer 2

Step-by-step explanation:

(x-y)^3 = x^3 -y^3 -3x^2y +3xy^2

= x^3-y^3 -3x^2y + 3xy^2 -(x^3-y^3-3x^2y +3xy^2)

= x^3 -y^3 -3x^2y +3xy^2 - x^3 +y^3 + 3x^2y - 3xy^2

= 0