Question

(x+y)³=x³+y³+3xy(x+y)

Answer 1

Step-by-step explanation:

we know that

$( {x + y})^{3} = {x}^{3} + {y}^{3} + 3 {x}^{2}y + 3x {y}^{2}$

by taking our common...

$= {x}^{3} + {y}^{3} + 3xy(x + y)$

hence proved

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Answer 2

${(x + y)}^{3} = {(x + y)}^{2}(x + y) \\ ( {x}^{2} + {y}^{2} + 2xy)(x + y) \\ {x}^{3} + {x}^{2} y + {y}^{2} x + {y}^{3} + 2 {x}^{2} y + 2 {y}^{2}x \\ {x}^{3} + {y}^{3} + 3xy(x + y)$

LHS = RHS

Hence ,Prooved