Question

x-y=3,xy=10 then x square+y square=?
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Answer 1

Given -

x-y = 3 (I)

xy = 10 (II)

Squaring both sides of (I) equation,

$= {(x - y)}^{2} = {3}^{2}$

$= {x}^{2} - 2xy + {y}^{2} = 9$

$= {x}^{2} + {y}^{2} - 2xy = 9$

Substituting eq (II) in above,

$= {x}^{2} + {y}^{2} - 2(10) = 9$

$= {x}^{2} + {y}^{2} - 20 = 9$

$= {x}^{2} + {y}^{2} = 29$

Henceforth, the value of the required expression is 29.

Answer 2

Answer:

Step-by-step explanation:

[x-y]²=x²-2xy+y²

3²     =x²-2*10+y²

9       =x²-20+y²

x²+y²=20+9

        =29

hope it helps u

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