Question

x+y/4=11;5x/6-y/3=17

Answer 1

Step-by-step explanation:

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Answer 2

The solution is $\mathbf{(x,y)=(\dfrac{190}{13},\dfrac{-47}{13})}$.

Step-by-step explanation:

The given system of equations :

$x+\dfrac{y}{4}=11------------(1)\\\\ \dfrac{5x}{6}-\dfrac{y}{3}=17---------(2)$

Multiply 8 on both sides of equation 1 and 6 on the both sides of equation 2 , we get

$8(x+\dfrac{y}{4})=88\\\ 8x+2y=88----------(3)\\\\ 6(\dfrac{5x}{6}-\dfrac{y}{3})=6\times17\\\ 5x-2y=102-----------(4)$

Add (3) and (4), we get

$13x=190\\\\ x=\dfrac{190}{13}$

Put value pf x in (1), we get

$\dfrac{190}{13}+\dfrac{y}{4}=11\\\\\Rightarrow\ \dfrac{y}{4}=11-\dfrac{190}{13}\\\\\Rightarrow\ \dfrac{y}{4}=\dfrac{-47}{13}$

Hence, the solution is $(x,y)=(\dfrac{190}{13},\dfrac{-47}{13})$

# Learn more :

Solve the following system of linear equations 103x+51y=617, 97x+49y=583

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