X+y=42,x-y=16 then find the values ofx and y
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2
Answer:
x+y=42
x-y=16
______
2x=58
x= 58/2
x=29
29+y= 42
y= 42-29
y= 13
Answered by
2
let x+y =42 be equation 1 añd x-y =16 be equation 2 . add equation 1 and 2.it will become 2x=58 . therefore,x=58/2=29
y=42-29=13
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