Question

x+y=48 and x+4=5/2(y+4) method of elimination

Answer 1

asper the question
x+y=48...(1)
x+4=5/2(y+4)
x+4=5y/2+20/2
x+4= take LCM.. 5y+20
2
2(x+4)=5y+20
2x+8=5y+20
2x-5y=20-8
2x-5y=12.......(2)
multiplying eq(1). by 2 & eq(2) by 1, we get..
2x+2y=96...(3)
2x-5y=12..(4)
Now subtracting eq (3) &(4).
2x+2y=96
2x-5y=12
(-) (+). (-)
7y=84
y=84/7
y=12
putting the value of y in eq (1)
x+y=48
x+12=48
x=48-12
x=36..
I hope this is the answer

Answer 2

Answer:

Step-by-step explanation:

x+y=48 x+4=5/2(y+4)