Question

x+y=5 and 2x-3y=4 solve the pair of linear equation by the elimination and substitution method
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Answer 1

HEY MATE HERE IS YIUR ANSWER:-

x+y=5----->i

2x-3y=4------>ii

elimination method

multiplying (i) with 3

eq:-3x+3y=15------>iii

Adding ii and iii

3x+3y=15

+ 2x-3y=4

=5x=19

x=19/5

y=5-19/5

y=(25-19)/5

y=6/5

Substitution method

x+y=5----->i

2x-3y=4----->ii

form (i)

x=5-y

substituting in.(ii)

2(5-y)-3y=4

10-2y-3y=4

-5y=-6

y=6/5

substituting y in (i)

x=5-6/5

x=19/5

HOPE IT WILL HELP U FOLLOW ME.....

Answer 2

By elimination method,x=19/5 and y=6/5

by substitution method,x=19/5 and y=6/5

Step-by-step explanation:

By elimination method

$x+y=5\times3-(i)\\2x-3y=4\times1-(ii)$

After solving equation (i) and (ii) we get,

$5x=19\\x=\frac{19}{5}$

Put $x=\frac{19}{5}$ in equation (i)

$x+y=5\\\frac{19}{5}+y=5\\y=5-\frac{19}{5}\\y=\frac{25-19}{5}\\y=\frac{6}{5}$

By substitution method

$x+y=5-(i)\\2x-3y=4-(ii)$

x = 5-y from equation (i)

Put x = 5y in equation (ii)

$2(5-y)-3y=4\\1-2y-3y=4\\10-5y=4\\-5y=4-10\\y=\frac{6}{5}$

Put y = $\frac{6}{5}$ in equation (i)

$x=5-\frac{6}{5}\\x=\frac{19}{5}$