x-y=5,x+y=15 find xy and x^2+y^2
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x²+y²=(x+y)²-2xy or, (x-y)²+2x
Given that, (x+y)=15 and (x-y)=5
So, 15²-2xy=5²+2xy
→225-25=2xy+2xy
→4xy=200
→xy=200/4=50
Hence, xy=50
Therefore, (x²+y²)=5²+2×50=125.
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