Question

x-y=6 and x²+y²=30 find value of x​

Answer 1

Answer:

X=8

Step-by-step explanation:

X^2+y^2=(x-y)^2+2xy

30=(6)^2+2xy

30=36+2xy

30-36=2xy

-6=2xy

Xy=-3

X=-3/y

Substitute x value in x-y=6

Then,-3/y-y=6

-3-y^2/y=6

3y^2/y=6

3y=6

Y=6/3=2

Substitute y value in x-y=6

X-2=6

X=6+2=8.