x-y=6 and xy=8 find x2+y2
Answers
Answered by
1
x²+y²
= (x-y)² + 2xy
= 6² + 16
= 36+16
= 52
Answered by
0
(x-y)^2=36
x^2+y^2-2xy=36
x^2+y^2=36+2*8
x^2+y^2=52
x^2+y^2-2xy=36
x^2+y^2=36+2*8
x^2+y^2=52
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