x-y=7 and xy=9 find the value of x2+y2
Answers
Answered by
0
We have,
x-y =7, x-y =9
We know
(x-y)^2 = x^2 + y^2 -2xy
(7)^2 = x^2 + y^2 - 2(9)
49 = x^2 + y^2 - 18
49+18 = x^2 + y^2
67 = x^2 + y ^2
I.e. x^2 + y^2 = 67. Ans
x-y =7, x-y =9
We know
(x-y)^2 = x^2 + y^2 -2xy
(7)^2 = x^2 + y^2 - 2(9)
49 = x^2 + y^2 - 18
49+18 = x^2 + y^2
67 = x^2 + y ^2
I.e. x^2 + y^2 = 67. Ans
Answered by
0
hey mate!!
as x-y=7so
x=7+y
and xy=9
so x=9/y
you can fill any valuein x2+y2
(9/y)2+(9/x)2=0
81/y2+81/x2=0
81x2+81y2=0
81(x2+y2)=0
x2+y2=0
as x-y=7so
x=7+y
and xy=9
so x=9/y
you can fill any valuein x2+y2
(9/y)2+(9/x)2=0
81/y2+81/x2=0
81x2+81y2=0
81(x2+y2)=0
x2+y2=0
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