X-y=7 xy=9 find the value of x2+y2
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(x-y) = 7
x2 + y2 - 2xy = 49
x2 + y2 - 18 = 49
x2 + y2 = 67
x2 + y2 - 2xy = 49
x2 + y2 - 18 = 49
x2 + y2 = 67
Answered by
10
Correct Question :-
If x - y = 9 and xy = 9, then find the value of x² + y².
Answer :-
x² + y² = 67
Solution :-
We know that
(x - y)² = x² + y² - 2xy
Here
• x - y = 7
• xy = 9
By substituting the values
⇒ (7)² = x² + y² - 2(9)
⇒ 49 = x² + y² - 18
Transpose - 18 to LHS
⇒ 49 + 18 = x² + y²
⇒ 67 = x² + y²
⇒ x² + y² = 67
Therefore the value of x² + y² is 67.
Verification :-
(x - y)² = x² + y² - 2xy
⇒ (7)² = 67 - 2(9)
⇒ 49 = 67 - 18
⇒ 49 = 49
Identity used :-
• (x - y)² = x² + y² - 2xy
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