√x+y =7 √y+x=11 find the value of x and y
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Answer:x + √y = 7 and √x + y = 11
Consider
√x + y = 11
√x = 11 - y
Squaring on both sides
x = 121 - 22y + y2
Put x = 121 - 22y + y2 in the equation x + √y = 7
Let √y = z
we get 121 + z4 - 22z2 + z = 7
We get factors z = ± 1, ± 2, ± 3, ± 6, ± 19, ± 57, ± 114
z = 3 satisfies the equation.
Now find the value of x and y we get x = 4 and y = 9
Step-by-step explanation:
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