Question

x+y-8=0 , 2x-3y-1 =0​

Answer 1

$<marquee>Hey Dear User !!!!!</marquee>$


$x + y - 8 = 0 \\ x + y = 8 \:\:\:\:\:\:\:\:\:\:\:\:----- (1)$

$2x - 3y - 1 = 0 \\ 2x - 3y = 1 \:\:\:\:\:\:\:\:\:\:\:\:\:\:------ (2)$

Here,

$x= 8 - y$

Putting value of x in equation 2, we get

$2(8 - y) - 3y = 1 \\ 16 - 2y - 3y = 1 \\ 16 - 5y = 1 \\ 16 - 1 = 5y \\ 15 = 5y \\ { \boxed{ y = \frac{15}{5} = 3}}$





${ \boxed{ \huge{Hence, \: We \: \: got \: \: the \: \: value \: \: of \: \: y \: \: as \: \: 3.}}} \\ \\ { \boxed{ \huge{ Therefore, \: the \: \: value \: \: of \: \: x \: \: will \: \: be \: \: 5}}}$

Answer 2

Answer:

Step-by-step explanation:

x+y-8=0 ........(1)

2x-3y-1=0 ........(2)

Equ(1)×2=2x+2y-16=0

Equ(2)×2=2x-3y-1=0

_______(-)__(+)_(+)___________

=> -y-15 = 0

=> y= -15