Question

x-y=8, 3x-3y=16 plz give me the solution

Answer 1

x-y=8
3x-3y=16
=3(x-y)=16
=3(8)=16
=24=16
=question is wrong......

Answer 2

Answer:

No solution

Step-by-step explanation:

Given pair of linear equations :

x-y-8 = 0 ---(1),

3x-3y-16 = 0 ---(2)

$Compare \:these \: equations \\with \: a_{1}x+b_{1}y+c_{1}=0\\and\\a_{2}x+b_{2}y+c_{2}=0,\\we\:get$

$a_{1}=1, \:b_{1}=-1 ,\:c_{1}=-8 \\a_{2}=3, \:b_{2}=-3 ,\:c_{2}=-16$

$\frac{a_{1}}{a_{2}}=\frac{1}{3}$

$\frac{b_{1}}{b_{2}}=\frac{-1}{-3}=\frac{1}{3}$

$\frac{c_{1}}{c _{2}}=\frac{-8}{-16}=\frac{1}{2}$

Therefore,

$\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}≠\frac{c_{1}}{c_{2}}$

Given lines are parallel to each other.

No solution.

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