X+y=8, xy = 15 find x2+y2
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Answered by
2
heya here's your answer
________
(x+y)^2=x^2+y^2+2xy
x^2+y^2=(x+y)^2-2xy
=8^2-(2*15)
=64-30
x^2+y^2 =34
hope it helps you
________
(x+y)^2=x^2+y^2+2xy
x^2+y^2=(x+y)^2-2xy
=8^2-(2*15)
=64-30
x^2+y^2 =34
hope it helps you
Answered by
0
A.T.Q.
x+y=8 and xy=15
Then in order to find x2+y2
We ll find it as:
(X+Y)^2= X^2 + Y^2 +2*X*Y
8^2 = x2+y2+2*15
64 =x2+y2+30
x2 +y2 = 64-30 = 34
x+y=8 and xy=15
Then in order to find x2+y2
We ll find it as:
(X+Y)^2= X^2 + Y^2 +2*X*Y
8^2 = x2+y2+2*15
64 =x2+y2+30
x2 +y2 = 64-30 = 34
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