Question

x+y = 96 and 4x+2y = 76 ,find x and y​

Answer 1

Answer:

$x = 96 - y \\ put \: value \: you \: ar \: left \: with \: your \: answer$

Answer 2

HEY MATE.......

$question \\ x + y = 96 \\ 4x + 2y =76 \\ find \: x \: and \: y$

If x + y = 96, then it follows that two times (x + y) is equal to two times (96), which is (192).

).Represented mathematically, this is 2(x + y) = 192.

By the distributive property, this is 2x + 2y = 192

We can rewrite 4x + 2y = 76 as (2x + 2x) + 2y = 76.

Because we know (2x + 2y is equal to 192), we can subtract (192) from the right side of (2x + 2x + 2y = 76), while we can subtract (2x + 2y) from the left.

), while we can subtract (2x + 2y) from the left.This leaves us with 2x = 34, meaning that x is 34/2, AKA 17.

), while we can subtract (2x + 2y) from the left.This leaves us with 2x = 34, meaning that x is 34/2, AKA 17.Plugging this value back into x + y = 96 yields 17 + y = 96. y must be 16.

. y must be 16.Thus, (x, y) = (17, 16)

. y must be 16.Thus, (x, y) = (17, 16)*The above method used is elimination. Substitution is also an option. However, using substitution may not be as efficient for this problem. I would recommend you consult an algebra textbook to further your understanding.