Question

X, y and z are positive integers such that when x is divided by y the remainder is 3 and when y is divided by z the remainder is 8. What is the smallest possible value of x+y+z? A. 12 b. 20 c. 24 d. 29 e. 33

Answer 1

Answer:

Step-by-step explanation:The answer is 33 becaus x/y=3 so we can say x=3y and y/z=8 similarly y=8z

X+y+z=3×8+1+8=33