Question

x,y and "z" be real numbers satisfying "(x)/(y+z)+(y)/(z+x)+(z)/(x+y)=1, find​

Answer 1

Answer:

Step-by-step explanation:

x+y+z=0

x+y=-z…………(1) , cubing both sides

x^3+y^3+3.x.y(x+y)=-z^3 , now put x+y= -z

x^3+y^3–3x.y.z=-z^3

x^3+y^3+z^3 =3.x.y.z , divide both sides by x.y.z

x^2/yz+y^2/zx+z^2/xy= 3 , answer.

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