Question

x, y and z have some monkey in ratio of 4:3:8 .if 2 monkeys are run away from x and 4 moneyks are run away from z then the ratio is 3:3:8.how many monkeys are intialy had? ​

Answer 1

Answer:

Total monkeys = 30

No. of monkeys with X  = 8

No. of monkeys with Y  = 6

No. of monkeys with Z  = 16

Step-by-step explanation:

Let the common ratio is x

Then

The number of monkeys with X = 4x

The number of monkeys with Y = 3x

The number of monkeys with Z = 8x

According to the question

(4x-2) : 3x : (8x-4) = 3 : 3 : 8

Therefore

4x - 2 = 3k

3x = 3k ⇒ x = k

4x - 2 = 3x

or, x = 2

No. of monkeys with X = 4 × 2 = 8

No. of monkeys with Y = 3 × 2 = 6

No. of monkeys with Z = 8 × 2 = 16

Note: Some data seems wrong