Math, asked by vony6367, 1 year ago

X,y are odd and z is even then ((x^2+y^2)z^2)/8 is

Answers

Answered by sswaraj04
0

Answer:

Step-by-step explanation:

anything multiplied to even is even

z is even

so, z^2 is even

(x^2+y^2)z^2 is even also

now dividing by 8 would give an even number as well...

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