Question

X + Y ka whole cube + 4 Into X + Y ka whole square + 4 x + 4 Y answer​

Answer 1

Answer:

${(x + y)}^{3} + 4( {x + y})^{2} + 4x + 4y$

$= {x}^{3} + {y}^{3} + 2xy(x + y) + 4 {x}^{2} \\ + 4 {y}^{2} + 8xy + 4x + 4y$

$= {x}^{3} + {y}^{3} + 2 {x}^{2}y + 2x {y}^{2} + 4 {x}^{2} \\ + 4 {y}^{2} + 8xy + 4 x+ 4y$

$= {x}^{3} + {y}^{3} + 4 {x}^{2} + 4 {y}^{2} \\ + 2 {x}^{2} y + 2 x{y}^{2} + 4 x+ 4 y+ 8xy$