Question

x + y = minus 1 and 2x minus 3y = minus 5 by substituition method.​

Answer 1

Step-by-step explanation:

Given -

• x + y = -1
• 2x - 3y = -5

To Find -

• Value of x and y by substitution method

Now,

→ x + y = -1

→ y = -1 - x

• Now, Substituting the value of y on 2x - 3y = - 5

→ 2x - 3(-1 - x) = -5

→ 2x + 3 + 3x = -5

→ 5x = -8

→ x = -8/5

• Now, Substituting the value of x on y = -1 - x

→ y = -1 - (-8/5)

→ y = -1 + 8/5

→ y = -5 + 8/5

→ y = 3/5

Hence,

The value of x is -8/5 and y is 3/5.

Answer 2

Given :

x + y = -1 --- eq (i)

2x - 3y = -5 ---- eq (ii)

To find :

The value of x and y by substituition method

Solution :

The eq (ii) can be written as ,

2x = (-5 + 3y)

x = (-5 + 3y)/2

Put the value of x = (-5 + 3y)/2 in eq (i) , we get

$\sf \hookrightarrow \frac{ - 5 + 3y}{2} + y = - 1 \\ \\ \sf \hookrightarrow - 5 + 3y + 2y = - 2 \\ \\ \sf \hookrightarrow - 5 + 5y = - 2 \\ \\ \sf \hookrightarrow5y = 3 \\ \\ \sf \hookrightarrow y = \frac{3}{5}$

Now, put the value of y = 3/5 in eq (i) , we get

$\sf \hookrightarrow x + \frac{3}{5} = - 1 \\ \\ \sf \hookrightarrow x = - 1 - \frac{3}{5} \\ \\ \sf \hookrightarrow x = - \frac{8}{5}$

$\therefore \sf \underline{The \: value \: of \: x \: and \: y \: are - \frac{8}{5} \: and \: \frac{3}{5} }$