X + Y = to a + b and it's a minus b y equal to a square minus b square solve the following linear simultaneous equations in two variables by the method of elimination
Attachments:
Answers
Answered by
34
your ask very nice question
given that
x+y=a+b. -1
ax-by=a^2-b^2
=ax-by=(a-b)(a+b)
=ax-by=(a-b)(x+y)
=ax-by=ax+ay-bx-bx
=ay-bx =0
=ay=bx
ax-by=a^2-b^2. -1
ay-bx=0. -2
y×(1). x×(2)
axy-by^2=y(a^2-b^2)
axy-bx^2=0
substraction both sides you get
b(x^2-y^2)=y*(a^2-b^2)
b={y(a-b)(a+b)}/(x-y)(a+b)
b=y(a-b)/(x-y)
by putting the value of b you get a
please follow me and tag me as brainlist
=
given that
x+y=a+b. -1
ax-by=a^2-b^2
=ax-by=(a-b)(a+b)
=ax-by=(a-b)(x+y)
=ax-by=ax+ay-bx-bx
=ay-bx =0
=ay=bx
ax-by=a^2-b^2. -1
ay-bx=0. -2
y×(1). x×(2)
axy-by^2=y(a^2-b^2)
axy-bx^2=0
substraction both sides you get
b(x^2-y^2)=y*(a^2-b^2)
b={y(a-b)(a+b)}/(x-y)(a+b)
b=y(a-b)/(x-y)
by putting the value of b you get a
please follow me and tag me as brainlist
=
Answered by
1
Answer:
Step-by-step explanation:
x+y=a+b. -1
ax-by=a^2-b^2
=ax-by=(a-b)(a+b)
=ax-by=(a-b)(x+y)
=ax-by=ax+ay-bx-bx
=ay-bx =0
=ay=bx
ax-by=a^2-b^2. -1
ay-bx=0. -2
y×(1). x×(2)
axy-by^2=y(a^2-b^2)
axy-bx^2=0
substraction both sides you get
b(x^2-y^2)=y*(a^2-b^2)
b={y(a-b)(a+b)}/(x-y)(a+b)
b=y(a-b)/(x-y)
by putting the value of b you get a
Similar questions
Math,
8 months ago
India Languages,
8 months ago
English,
8 months ago
Physics,
1 year ago
English,
1 year ago