x+y/x-y=3 then x^2+5xy-y^2/3x^2+7y^2=WHAT
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x+y/x-y=3
x+y=3x-3y
3x-3y-x-y=0
2x-4y=0
x=2y
=(2y)^2+5(2y) -y^2/3(2y)^2 +7y^2
=4y2 + 10y^2-y^2/12y^2+7y^2
=13y^2/19y^2
=13/19
x+y=3x-3y
3x-3y-x-y=0
2x-4y=0
x=2y
=(2y)^2+5(2y) -y^2/3(2y)^2 +7y^2
=4y2 + 10y^2-y^2/12y^2+7y^2
=13y^2/19y^2
=13/19
vichu4:
thanks
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