x-y=x+y/7=xy/4 then the numerical value of xy=?
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Answered by
56
☆☆heya your answer is here☆☆
x_y=x+y/7=x*y/4 =k (suppose that)
then x-y=k (1)
& x+y=7k (2)
by solve equ. 1 &2
x=4k, y=3k
we know that
x*y=4k
12k^2=4k
k=1/3
x*y=4/3
x_y=x+y/7=x*y/4 =k (suppose that)
then x-y=k (1)
& x+y=7k (2)
by solve equ. 1 &2
x=4k, y=3k
we know that
x*y=4k
12k^2=4k
k=1/3
x*y=4/3
Anonymous:
hii
Answered by
0
Given : x-y=x+y/7=xy/4
To Find : numerical value of xy
Solution:
x - y = (x + y)/7 = xy/4
Taking 1st 2 equations
x - y = (x + y)/7
=> 7x - 7y = x + y
=> 6x = 8y
=> 3x = 4y
=> x = 4y/3
x -y = 4y/3 - y = y/3
(x + y)/7 = y/3
xy/4 = (4y/3).y/4 = y/3
=> y = 1
x = 4y/3 => x = 4/3
Hence x = 4/3
y = 1
xy = 4/3
x - y = 1/3
(x + y)/7 = 1/3
xy/4 = 1/3
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