x - y^x-y, where x = 2 and y = -2
aksharma1994:
-14
Answers
Answered by
0
2-(-2)^2-(-2) = 2-4+2 = 0
(x-y) power me hai
kk
oo
then ans will be.....
2-(-2)^(2-(-2))=2-(-2)^4=2-16=-14
sorry for the mistake
Answered by
1
2-(-2)^{2-(-2)}=2-2^4=2-16=-14 is the answer ! hope it helped you ! thank you !
now it's okk!
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