Question

(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x)​

Answer 1

VERY SIMPLE DUDE

NOW

(A+B) (A-B) = A²-B²

BY APPLYING PROPERTY

= X²-Y²+Y²-Z²+Z²-X²

= 0

HENCE FINDED...

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