Question

x/y+y/x=-1 and y not =0 then find x cube+ y cube

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Answer 1

Answer:

We know that,

x³-y³=(x-y)(x²+xy+y²)........................1

Given that,

x/y+y/x=-1

(x²+y²)/xy=-1

x²+y²=-xy

x²+y²+xy=0

(x²+xy+y²)=0

Multyplying by (x-y) on both sides we get,

(x-y)(x²+xy+y²)=(x-y)×0

eq1 we get,

x³-y³=0

Hence x³-y³=0.

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