x/y+y/x=1 then x³+y³=
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Step-by-step explanation:
We know that,x3 - y3 = (x - y)(x² + xy + y²) ....(i)
Given that, x/y + y/x = -1
(x² + y²)/xy = -1
x² + y² = -xy
x² + y² + xy = 0
(x² + xy + y²) = 0
Multyplying by (x - y) on both sides we get,(x - y)(x² + xy + y²) = (x - y) × 0
x3 - y3 = 0 using (i)
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