Question

X÷y+y÷x=-1,x cube-ycube

Answer 1

Heya

Put x = y | We see that the given equation isn't satisfied and hence, x is not equal to 1

Now, simplify :
$\frac{x}{y} + \frac{y}{x} = - 1$

$= > \frac{ {x}^{2} + {y}^{2} }{xy} = - 1$

$= > {x}^{2} + {y}^{2} + xy = 0$

Multiplying ( x - y ) both sides :
$({x}^{3} - {y}^{3} ) = 0$
Hence, the desired value is zero