X^✓y +y^✓x =49/48
and
✓x+✓y=7/2
find the value x and y
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√x+√y=7/2
(cross multiply)
[2(√x+√y)]/7 ----i
x^√y+y^√x=49/48
(cross multiply)
[48(x^√y+y^√x)]/49 -----ii
from i and ii
i=ii
(48x^√y+48y^√x)/49=(2√x+2√y)/7
cancelling denominator
(48x^√y+48y^√x)/7=2√x+2√y
cross multiply
48x^√y+48y^√x=14√x+14√y
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