x^Y=y^x and Y=x^2 find x and y
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Given,
x^y=y^x. equa. (1)
And, y=x^2
By putting y=x^2 in equation (1)
We have ,
x^x^2=x^2x
By comparison,
x^2=2x
so either x=2 or 0.
so by putting x=2 or 0
we will get
y=4 or 0
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