Question

x+y-z=0
x-2y+z=0
3x+6y-5z=0

Answer 1

Answer:

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Answer 2

$x + y - z = 0 \: ----- (1)$

$x - 2y + z = 0 - - - - - (2)$

$3x + 6y - 5z = 0 - - - - - (3)$

$eqn(1) + eqn (2)$

$\binom{x + y - z = 0}{ + (x - 2y + z = 0)} = 2x - y = 0 - - - - - (4)$

$eqn(2) \times 5 + eqn(3)$

$\binom{5x - 10y + 5z = 0}{ + (3x + 6y - 5z = 0)} = 8x - 4y = 0 - - - - - (5)$

$eqn(4) \times 4 - eqn(5)$

$\binom{8x - 4y = 0}{ - (8x - 4y = 0)} = 0$

$therefore....$

$x = 0$

$y = 0$

$z = 0$