x + y + z=0, xcube + ycube +zcube=3xyz
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i am using ^3 =*
we know that
x*+y*+z*-3xyz= (x+y+z) (x^2 +y^2+z^2 -xy - yz - zx) ...... ( eq.1)
a/q x+y+z=0
so putting the value of x+y+z=0 on eq1 we get
x*+y*+z*-3xyz=0
from here we get x*+y*+z*=3xyz
we know that
x*+y*+z*-3xyz= (x+y+z) (x^2 +y^2+z^2 -xy - yz - zx) ...... ( eq.1)
a/q x+y+z=0
so putting the value of x+y+z=0 on eq1 we get
x*+y*+z*-3xyz=0
from here we get x*+y*+z*=3xyz
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