x+y+z=0, xy+yz+zx=1/3, x^2+y^2+z^2=-1/3, x:y:z=?
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Given Data is Wrong , x+y+z=0, xy+yz+zx=1/3, x^2+y^2+z^2=-1/3, x:y:z=?
Step-by-step explanation:
(x + y + z) = 0
Squaring both sides
=> (x + y + z)² = 0²
=> x² + y² + z² + 2(xy + yz + zx ) = 0
=> -1/3 + 2(1/3) =0
=> 1/3 = 0
Which is not True
=> Data Given is wrong
Similar Question if
(x + y + z) = 1 & xy+yz+zx=1/3, then find x:y:z
=> x² + y² + z² + 2(xy + yz + zx ) = 1
=> x² + y² + z² = 1/3
xy+yz+zx = 1/3
Which will hold true if
x = y = z
=> x : y : z ::: 1: 1: 1
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