x×y⁰×z‐¹ Fill in the blank?
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Given : x×y⁰×z‐¹
To find : Simplify
Solution:
x×y⁰×z‐¹
x = x
y⁰ = 1 ( as number raised to power 0 = 1 )
z⁻¹ = 1/z¹
=> z⁻¹ = 1/z
substituting these values in x×y⁰×z‐¹
= x × 1 ×( 1/z)
x × 1 = x
= x ×( 1/z)
= x/z
x×y⁰×z‐¹ = x/z
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