Question

x+y+z=1, xy +yz +xz=-1& xyz=-1 find x^3 +y ^3+ z^3

Answer 1

Answer:

x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)

x³+y³+z³=(x+y+z)(x²+y²+z²-xy-yz-zx)+3xyz

x³+y³+z³=1x(x+y+z)²-1+3x-1

=1-1-3

=-3

Answer 2

Answer:

3

Step-by-step explanation:

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