Question

X+y+z=19, xy+yz+zx=114,then the value of ✓(x^3+y^3+z^3-3xyz) is

Answer 1

Answer:

19

Step-by-step explanation:

(x+y+z)2=x2+y2+z2+2(xy+yz+zx)

from above we get

x2+y2+z2=133

(x3+y3+z3)=3xyz+(axbxc)(a2+b2+c2-xy-yz-zx)

x3+y3+z3-3xyz=(19)(133-114)

19x19

361

root of answer =19