Question

x : y : z = 4:3:2 and x 2+ y 2+ z 2 = 11600, then the value of √x+y-z​

Answer 1

Answer:

x:y:z=4k:3k:2k

• (16+9+4)k=11600
• 29k=11600
• k=11600/29
• k=400
• $\sqrt{x + y - z}$
• $\sqrt{400 \times 4 + 400 \times 3 - 400 \times 2}$
• $( \sqrt{4 + 3 - 2} ) \times 20$
• $\sqrt{5 } \times 20$

Answer 2

Answer:

$\sqrt{x+y-z} =10$

Step-by-step explanation:

Let x = 4k, y = 3k and z = 2k

$x^{2} +y^{2} +z^{2} = (4k)^{2}+(3k)^{2}+(2k)^{2} = 29k^{2}$

$29k^{2} = 11600$

$k^{2} = \frac{11600}{29}$

= 400

k = 20

So,

x = 4k = 4(20) = 80

y = 3k = 3(20) = 60

z = 2k = 2(20) = 40

$\sqrt{x+y-z} = \sqrt{80+60-40}$

$=\sqrt{100}$

= 10