Question

X+Y+Z= 5
YY+ ZX =25
XZ- ZY= 28
X + YZ =WHAT

Answer 1

Answer:

0

Step-by-step explanation:

By adding all the three equations.

x+y+z+xy+yz+zx+xyz+1=6+15+14+1=36

=> (x+1)*(y+1)*(z+1) =36.= 1*2*18 = 2*3*6= 1*3*12 = -1*-2*18=……..

=> By solving LHS with each of the RHS values , we get many non-negatve, negative and zero solutions of x,y,z.

But as xyz not equal to zero => x,y,z not equal to zero.

Select the x,y,z pairs to satisfy the above conditions.

But here, in this it's time consuming.

Method-2.

X(y+z)+yz=15

X(6-x) + 14/X = 15

6x-x^2+14/x =15

6x^2 - x^3 +14 =15x

=> X^3 - 6x^2 +15x -14= 0

Answer 2

Answer:

Zero is the required answer bro

Please mark me as a brainliest pleaseeeeeeeee...