Question

x+y+z=9 and xy+yz+zx=23 find the value of xpower2 ypower2 zpower2

Answer 1

Hey mate!

Here is your answer > >

x+y+z=9

Squaring both sides

(x+y+z)^2=9^2

x^2+y^2+z^2+2xy+2yz+2zx=81

x^2+y^2+z^2+2 (xy+yz+zx)=81

x^2+y^2+z^2+2 (23)=81

x^2+y^2+z^2+46=81

x^2+y^2+z^2=81-46

x^2+y^2+z^2=35

Hope it helps!

Thankyou ☆ ☆

Answer 2

hey
bro your answer is here.
sorry for late.